SATHEE: Atoms And Nuclei Question 169

Atoms And Nuclei Question 169

Question: Atomic weight of boron is 10.81 and it has two isotopes $_{5} B^{10}$ and $_{5} B^{11}$ . Then ratio of $ {5}B^{10}{:{5}}B^{11} $ in nature would be [CBSE PMT 1998; JIPMER 2001, 02]

Options:

A) 19 : 81

B) 10 : 11

C) 15 : 16

D) 81 : 19

Show Answer

Answer:

Correct Answer: A

Solution:

Let the percentage of $B^{10}$ atoms be x, then Average atomic weight $= \frac{10 x + 11 (100 - x)}{100} = 10.81$
$\Rightarrow x = 19 ∴ \frac{N_{B^{10}}}{N_{B^{11}}} = \frac{19}{81}$

Atoms And Nuclei Question 169

Question: Atomic weight of boron is 10.81 and it has two isotopes $_{5} B^{10}$ and $_{5} B^{11}$ . Then ratio of $ {5}B^{10}{:{5}}B^{11} $ in nature would be [CBSE PMT 1998; JIPMER 2001, 02]

Options:

Answer:

Solution:

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Atoms And Nuclei Question 169

Question: Atomic weight of boron is 10.81 and it has two isotopes 5B10 and 5B11 . Then ratio of $ {5}B^{10}{:{5}}B^{11} $ in nature would be [CBSE PMT 1998; JIPMER 2001, 02]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: Atomic weight of boron is 10.81 and it has two isotopes $_{5} B^{10}$ and $_{5} B^{11}$ . Then ratio of $ {5}B^{10}{:{5}}B^{11} $ in nature would be [CBSE PMT 1998; JIPMER 2001, 02]