SATHEE: Atoms And Nuclei Question 167

Atoms And Nuclei Question 167

Question: Radius of $_{2}^{4} H e$ nucleus is 3 Fermi. The radius of $3 \to 2$ nucleus will be [CPMT 1999]

Options:

A) 5 Fermi

B) 6 Fermi

C) 11.16 Fermi

D) 8 Fermi

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Answer:

Correct Answer: C

Solution:

We have $r \propto A^{1 / 3} \Rightarrow \frac{r_{2}}{r_{1}} = {(\frac{A_{2}}{A_{1}})}^{1 / 3} = {(\frac{206}{4})}^{1 / 3}$
$∴ r_{2} = 3 {(\frac{206}{4})}^{1 / 3} = 11.6 F e r m i$ .

Atoms And Nuclei Question 167

Question: Radius of $_{2}^{4} H e$ nucleus is 3 Fermi. The radius of $3 \to 2$ nucleus will be [CPMT 1999]

Options:

Answer:

Solution:

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Atoms And Nuclei Question 167

Question: Radius of 24He nucleus is 3 Fermi. The radius of 3→2 nucleus will be [CPMT 1999]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: Radius of $_{2}^{4} H e$ nucleus is 3 Fermi. The radius of $3 \to 2$ nucleus will be [CPMT 1999]