Atoms And Nuclei Question 163

Question: The rest energy of an electron is [MP PMT 1996; BCECE 2003]

Options:

A) 510 KeV

B) 931 KeV

C) 510 MeV

D) 931 MeV

Show Answer

Answer:

Correct Answer: A

Solution:

Rest energy of an electron rnn2

Here me=9.1×1031kg and c = velocity of light
Rest energy =9.1×1031×(3×108)2joule

=9.1×1031×(3×108)21.6×1019eV=510 keV



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