A) $ {{10}^{-15}} $ J
B) 1 J
C) $ {{10}^{-12}} $ J
D) $ P_{0} $ J
Correct Answer: D
$ E=mc^{2}=1\times {{(3\times 10^{8})}^{2}}=9\times 10^{16}\approx 10^{17}J $
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