Atoms And Nuclei Question 140
Question: An electron changes its position from orbit $ n=4 $ to the orbit $ n=2 $ of an atom. The wavelength of the emitted radiation’s is (R = Rydberg’s constant) [BHU 2004]
Options:
A) $ \frac{16}{R} $
B) $ \frac{16}{3R} $
C) $ \frac{16}{5R} $
D) $ \frac{16}{7R} $
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Answer:
Correct Answer: B
Solution:
$ \frac{1}{\lambda }=R[ \frac{1}{n_{1}^{2}}-\frac{1}{n_{2}^{2}} ]=R[ \frac{1}{{{(2)}^{2}}}-\frac{1}{{{(4)}^{2}}} ] $
Þ $ \lambda =\frac{16}{3R} $