Atoms And Nuclei Question 132

Question: Energy E of a hydrogen atom with principal quantum number n is given by E=13.6n2eV . The energy of a photon ejected when the electron jumps from n=3 state to n=2 state of hydrogen is approximately [CBSE PMT 2004]

Options:

A) 1.5 eV

B) 0.85 eV

C) 3.4 eV

D) 1.9 eV

Show Answer

Answer:

Correct Answer: D

Solution:

E32=3.4(1.51)=1.89,eV Þ |E32| 1.9,eV



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