SATHEE: Atoms And Nuclei Question 120

Atoms And Nuclei Question 120

Question: The de-Broglie wavelength of an electron in the first Bohr orbit is [KCET 2002]

Options:

A) Equal to one fourth the circumference of the first orbit

B) Equal to half the circumference of the first orbit

C) Equal to twice the circumference of the first orbit

D) Equal to the circumference of the first orbit

Show Answer

Answer:

Correct Answer: D

Solution:

$m v r_{n} = \frac{n h}{2 π} \Rightarrow p r_{n} = \frac{n h}{2 π} \Rightarrow \frac{h}{λ} \times r_{n} = \frac{n h}{2 π}$
$\Rightarrow λ = \frac{2 π r_{n}}{n},$ for first orbit $n = 1$ so $λ = 2 π r_{1}$ = circumference of first orbit

Atoms And Nuclei Question 120

Question: The de-Broglie wavelength of an electron in the first Bohr orbit is [KCET 2002]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Atoms And Nuclei Question 120

Question: The de-Broglie wavelength of an electron in the first Bohr orbit is [KCET 2002]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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