SATHEE: Atoms And Nuclei Question 114

Atoms And Nuclei Question 114

Question: Energy of an electron in an excited hydrogen atom is ? 3.4 eV. Its angular momentum will be: $h = 6.626 \times 10^{- 34} J - s$ [UPSEAT 1999; Kerala PET 2002]

Options:

A) $1.11 \times 10^{34} J \sec$

B) $1.51 \times 10^{- 31} J \sec$

C) $2.11 \times 10^{- 34} J \sec$

D) $3.72 \times 10^{- 34} J \sec$

Show Answer

Answer:

Correct Answer: C

Solution:

The electron is in the second orbit (n=2) Hence $L = \frac{n h}{2 π} = \frac{2 h}{2 π} = \frac{6.6 \times 10^{- 34}}{π}$ $= 2.11 \times 10^{- 34} J - s e c$

Atoms And Nuclei Question 114

Question: Energy of an electron in an excited hydrogen atom is ? 3.4 eV. Its angular momentum will be: $h = 6.626 \times 10^{- 34} J - s$ [UPSEAT 1999; Kerala PET 2002]

Options:

Answer:

Solution:

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Atoms And Nuclei Question 114

Question: Energy of an electron in an excited hydrogen atom is ? 3.4 eV. Its angular momentum will be: h=6.626×10−34J−s [UPSEAT 1999; Kerala PET 2002]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: Energy of an electron in an excited hydrogen atom is ? 3.4 eV. Its angular momentum will be: $h = 6.626 \times 10^{- 34} J - s$ [UPSEAT 1999; Kerala PET 2002]