SATHEE: Atoms And Nuclei Question 112

Atoms And Nuclei Question 112

Question: Four lowest energy levels of H-atom are . The number of possible emission lines would be [MP PMT 2001]

Options:

A) 3

B) 4

C) 5

D) 6

Show Answer

Answer:

Correct Answer: D

Solution:

Number of possible emission lines $= \frac{n (n - 1)}{2}$ Where n = 4; Number $= \frac{4 (4 - 1)}{2} = 6.$

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Atoms And Nuclei Question 112

Question: Four lowest energy levels of H-atom are . The number of possible emission lines would be [MP PMT 2001]

Options:

Answer:

Solution:

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