Atoms And Nuclei Question 112

Question: Four lowest energy levels of H-atom are . The number of possible emission lines would be [MP PMT 2001]

Options:

A) 3

B) 4

C) 5

D) 6

Show Answer

Answer:

Correct Answer: D

Solution:

Number of possible emission lines $ =\frac{n(n-1)}{2} $ Where n = 4; Number $ =\frac{4(4-1)}{2}=6. $



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