Atoms And Nuclei Question 100

Question: The radius of the Bohr orbit in the ground state of hydrogen atom is 0.5 Å. The radius of the orbit of the electron in the third excited state of $ H{{e}^{+}} $ will be [MP PMT 2000]

Options:

A) 8 Å

B) 4 Å

C) 0.5 Å

D) 0.25 Å

Show Answer

Answer:

Correct Answer: B

Solution:

By using $ r_{n}=r_{0}\frac{n^{2}}{Z} $ ;

Where r0 = Radius of the Bohr orbit in the ground state atom .

So for $ H{{e}^{+}} $ third excited state $ n=4,\ Z=2,\ r_{0}=0.5{\AA} $ Þ $ r_{4}=0.5\times \frac{4^{2}}{2}=4{\AA} $



NCERT Chapter Video Solution

Dual Pane