Some Basic Principles Of Organic Chemistry Question 83
Question: If a compound on analysis was found to contain C = 18.5%, H = 1.55%, Cl = 55.04% and O = 24.81%, then its empirical formula is [AIIMS 1998]
Options:
A) $ CHClO $
B) $ CH_2ClO $
C) $ C_2H_2OCl $
D) $ ClCH_2O $
Show Answer
Answer:
Correct Answer: A
Solution:
| Elements | No.of moles | Simple ratio |
|---|---|---|
| C = 18.5% | 18.5/12 1.54 | 1 |
| H = 1.55% | 1.55/1 1.55 | 1 |
| Cl = 55.04% | 55.04/35.5 1.55 | 1 |
| O = 24.81% | 24.81/16 1.55 | 1 |
Hence, formula = $ CHClO $ .
