Some Basic Principles Of Organic Chemistry Question 69
Question: An organic compound gave C = 92.31% and $ H=7.69% $ . If molecular weight of the compound is 78, its molecular formula is
Options:
A) $ C_6H_6 $
B) $ C_7H_7 $
C) $ C_6H_{18} $
D) $ C_8H_{20} $
Show Answer
Answer:
Correct Answer: A
Solution:
| Element | No.of Moles | Simple Ratio |
|---|---|---|
| C = 92.31 | 92.31/12 = 7.69 | 1 |
| H = 7.69 | 7.69/1 = 7.69 | 1 |
Hence, CH Empirical formula mass of CH = 13 $ n=\frac{Mol\text{.mass}}{Emp\text{.},mass}=\frac{78}{13}=6 $
Molecular formula = $ {{(CH)}_6}=C_6H_6 $ .
