Some Basic Principles Of Organic Chemistry Question 68
Question: An organic compound on analysis gave the following results : C = 54.5%, O = 36.4%, H = 9.1%. The Empirical formula of the compound is [CPMT 1977; KCET 1998; MP PET 2003; UPSEAT 2004; IIT-JEE (Screening) 2004]
Options:
A) $ CH_3O $
B) $ C_2H_4O $
C) $ C_3H_4O $
D) $ C_4H_8O $
Show Answer
Answer:
Correct Answer: B
Solution:
| Element | No.of Moles | Simple Ratio |
|---|---|---|
| C = 54.5 | 54.5/12 = 4.54 | 2 |
| H = 9.1 | 9.1/1 = 9.1 | 4 |
| O = 36.4 | 36.4/16 = 2.27 | 1 |
Hence, $ C_2H_4O $ .
