Some Basic Principles Of Organic Chemistry Question 68

Question: An organic compound on analysis gave the following results : C = 54.5%, O = 36.4%, H = 9.1%. The Empirical formula of the compound is [CPMT 1977; KCET 1998; MP PET 2003; UPSEAT 2004; IIT-JEE (Screening) 2004]

Options:

A) CH3O

B) C2H4O

C) C3H4O

D) C4H8O

Show Answer

Answer:

Correct Answer: B

Solution:

Element No.of Moles Simple Ratio
C = 54.5 54.5/12 = 4.54 2
H = 9.1 9.1/1 = 9.1 4
O = 36.4 36.4/16 = 2.27 1

Hence, C2H4O .



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