Some Basic Principles Of Organic Chemistry Question 65
Question: 60 g of a compound on analysis gave $ C=24g, $ $ H=4g $ and O = 32 g. Its Empirical formula is [CPMT 1971, 81]
Options:
A) $ C_2H_4O_2 $
B) $ C_2H_2O $
C) $ CH_2O_2 $
D) $ CH_2O $
Show Answer
Answer:
Correct Answer: D
Solution:
| Element | No.of Moles | Simple Ratio |
|---|---|---|
| C = 24 | 24/12 = | 2: 1 |
| H = 4 | 4/1 = | 4 :2 |
| O = 32 | 32/16 = | 2: 1 |
Therefore $ CH_2O $ .
