Some Basic Principles Of Organic Chemistry Question 64

Question: Empirical formula of a compound is C2H5O and its molecular weight is 90. Molecular formula of the compound is [NCERT 1971]

Options:

A) C2H5O

B) C3H6O3

C) C4H10O2

D) C5H14O

Show Answer

Answer:

Correct Answer: C

Solution:

Empirical formula mass = C2H5O = 24+ 5 +16= 45.

$ n=\frac{Mol\text{.

mass}}{Emp\text{.

mass}}=\frac{90}{45}=2 $ Mol.

formula = $ {{(C_2H_5O)}2}=C_4H{10}O_2 $ .



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