Some Basic Principles Of Organic Chemistry Question 64
Question: Empirical formula of a compound is $ C_2H_5O $ and its molecular weight is 90. Molecular formula of the compound is [NCERT 1971]
Options:
A) $ C_2H_5O $
B) $ C_3H_6O_3 $
C) $ C_4H_{10}O_2 $
D) $ C_5H_{14}O $
Show Answer
Answer:
Correct Answer: C
Solution:
Empirical formula mass = $ C_2H_5O $ = 24+ 5 +16= 45.
$ n=\frac{Mol\text{.
mass}}{Emp\text{.
mass}}=\frac{90}{45}=2 $ Mol.
formula = $ {{(C_2H_5O)}2}=C_4H{10}O_2 $ .
