Some Basic Principles Of Organic Chemistry Question 61
Question: An organic compound contains $ C=74.0%, $ $ H=8.65% $ and $ N=17.3% $ . Its Empirical formula is [MP PMT 1986]
Options:
A) $ C_5H_8N $
B) $ C_{10}H_{12}N $
C) $ C_5H_7N $
D) $ C_{10}H_{14}N $
Show Answer
Answer:
Correct Answer: C
Solution:
| Element | No.of Moles | Simple Ratio |
|---|---|---|
| C = 74 | 74/12 = 6.1 6.1/1.2 = | 5.08 or 5 |
| H = 8.65 | 8.65/1= 8.65 8.6/1.2 = | 7.16 or 7 |
| N = 17.3 | 17.3/14 = 1.2 1.2/1.2 = | 1 or 1 |
Therefore Empirical formula $ =C_5H_7N $ .
