SATHEE: Some Basic Principles Of Organic Chemistry Question 6

Some Basic Principles Of Organic Chemistry Question 6

Question: A straight chain hydrocarbon has the molecular formula $C_{8} H_{10}$ . The hybridisation for the carbon atoms from one end of the chain to the other are respectively $s p^{3}, s p^{2}, s p^{2}, s p^{3}, s p^{2}, s p^{2}, s p$ and $s p$ . The structural formula of the hydrocarbon would be [CBSE PMT 1992]

Options:

A) $C H_{3} - C \equiv C - C H_{2} - C H = C H - C H = C H_{2}$

B) $C H_{3} - C H_{2} - C H = C H - C H_{2} - C \equiv C - C H = C H_{2}$

C) $C H_{3} - C H = C H - C H_{2} - C \equiv C - C H = C H_{2}$

D) $C H_{3} - C H = C H - C H_{2} - C H = C H - C \equiv C H$

Show Answer

Answer:

Correct Answer: D

Solution:

$\underset{s p^{3}}{C H_{3}}, - \overset{s p^{2}}{C H}, = \underset{s p^{2}}{C H}, - \overset{s p^{3}}{C H_{2}}, - \underset{s p^{2}}{C H}, = \overset{s p^{2}}{C H}, - \underset{s p}{C}, \equiv \underset{s p}{C H},$

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Some Basic Principles Of Organic Chemistry Question 6

Question: A straight chain hydrocarbon has the molecular formula C8H10 . The hybridisation for the carbon atoms from one end of the chain to the other are respectively sp3,sp2,sp2, sp3,sp2,sp2,sp and sp . The structural formula of the hydrocarbon would be [CBSE PMT 1992]

Options:

Answer:

Solution:

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