Some Basic Principles Of Organic Chemistry Question 371
Question: Which will give chiral molecule [DPMT 2005]
Options:
A) $ CH_3COCl\xrightarrow{LiAlH_4} $
B) $ C_2H_5CHO\underset{{H^{+}}/H_2O}{\mathop{\xrightarrow{CH_3MgBr}}}, $
C) $ {{(CH_3)}_2}CHC_2H_5\xrightarrow{Cu} $
D) $ \begin{matrix} H \\ {} \\ CH_3 \\ \end{matrix}C=C\begin{matrix} CH_3 \\ {} \\ CH_3 \\ \end{matrix}\xrightarrow{Cl_2} $
Show Answer
Answer:
Correct Answer: B
Solution:
$ C_2H_5CHO\underset{{H^{+}}/H_2O}{\mathop{\xrightarrow{CH_3MgBr}}}\underset{CH_3}{\mathop{\underset{|}{\mathop{\overset{,H}{\mathop{\overset{|}{\mathop{C_2H_5-{C^{*}}-OH}},}},}},}}, $
$ {C^{*}} $ -chiral carbon as all the four valencies are attached with different substituents or groups.
