SATHEE: Some Basic Principles Of Organic Chemistry Question 364

Some Basic Principles Of Organic Chemistry Question 364

Question: The number of possible enantiomeric pairs that can be produced during mono-chlorination of 2-methylbutane is [Pb. CET 2004]

Options:

A) 3

B) 4

C) 1

D) 2

Show Answer

Answer:

Correct Answer: D

Solution:

$\overset{1}{C}, H_{3} - \underset{C H_{3}}{\underset{|}{\overset{2}{C}}, H -}, \overset{3}{C}, H_{2} - \overset{4}{C}, H_{3}$ Its monochloro derivatives are as follows : (i) $C l C H_{2} - \underset{C H_{3},}{\underset{|}{\overset{∙}{C}}, H -}, C H_{2} - C H_{3}$ or $C H_{3} - \underset{C H_{2} C l,}{\underset{|}{\overset{∙}{C}}, H - C H_{2}}, - C H_{3}$ It will exist as enantiomeric pair (d and l-forms) (ii) $C H_{3} - \underset{C H_{3},}{\overset{C l}{\underset{|}{\overset{|}{C}}, -}, C H_{2}}, - C H_{3}$ no asymmetric C atom (iii) $C H_{3} - \underset{C H_{3},}{\underset{|}{C}, H -}, \overset{C l}{\overset{|}{C}, H}, - C H_{3}$ It will exist as enantiomeric pair (d- and l-forms) (iv) $C H_{3} - \underset{C H_{3}}{\underset{|}{C}, H -}, C H_{2} - C H_{2} - C l$ No asymmetric carbon atom Hence, only two enantiomeric pairs will be obtained by the monochlorination of 2-methylbutane.

Some Basic Principles Of Organic Chemistry Question 364

Question: The number of possible enantiomeric pairs that can be produced during mono-chlorination of 2-methylbutane is [Pb. CET 2004]

Options:

Answer:

Solution:

Engineering Preparation

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Some Basic Principles Of Organic Chemistry Question 364

Question: The number of possible enantiomeric pairs that can be produced during mono-chlorination of 2-methylbutane is [Pb. CET 2004]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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