Some Basic Principles Of Organic Chemistry Question 329
Question: Which compound is optically active [DCE 1999]
Options:
A) 4-chloro, 1 hydroxy butane
B) $ 3^{o} $ -butyl alcohol
C) Secondary butyl amine
D) n-butyl alcohol
Show Answer
Answer:
Correct Answer: C
Solution:
$ \underset{{}}{\mathop{CH_3-\underset{,NH_2}{\mathop{\overset{H}{\mathop{\underset{|,}{\overset{|,}{\mathop{C,-}}},}},}},CH_2-CH_3}}, $ Secondary butyl amine is optically active.
