Some Basic Principles Of Organic Chemistry Question 319
Question: The number of enantiomers of the compound $ CH_3CHBrCHBrCOOH $ is [AIIMS 1997]
Options:
A) 0
B) 1
C) 3
D) 4
Show Answer
Answer:
Correct Answer: D
Solution:
$ CH_3-\underset{Br,}{\mathop{\underset{|}{\overset{\overset{H}{\mathop{|}},}{\mathop{{C _{*}}}}},}},-\underset{Br,}{\overset{H}{\mathop{\underset{|,}{\overset{|}{\mathop{{C _{*}}}}},}}},-COOH $ Number of enantiomers = $ 2^{n} $ (n = asymmetric Carbon atom) = $ 2^{2} $ = 4.
