Some Basic Principles Of Organic Chemistry Question 307
Question: The following compound can exhibits $ \begin{matrix} CH_3 \\ CH_3 \\ \end{matrix}>\underset{\begin{smallmatrix} \\ \ \ CH_3 \end{smallmatrix}}{\mathop{C=C}},\underset{\cancel{}}{\overset{{}}{\mathop{<}}},\begin{matrix} H \\ C< \\ \end{matrix}\begin{matrix} \underset{H\ \ \ \ \ ,}{\mathop{{}}}, \\ \underset{COOH}{\mathop{{}}}, \\ \end{matrix} $ [IIT-JEE 1995; DCE 2000]
Options:
A) Tautomerism
B) Optical isomerism
C) Geometrical isomerism
D) Geometrical and optical isomerisms
Show Answer
Answer:
Correct Answer: B
Solution:
Optical isomerism because chiral centre is present $ {{(CH_3)}_2}-C=CH-\underset{CH_3}{\overset{H}{\mathop{\underset{|}{\overset{|}{\mathop{{C^{*}},-,COOH}}},}}}, $ .
