Some Basic Principles Of Organic Chemistry Question 296

Question: The number of possible alcoholic isomers for C4H10O are [DPMT 1984; MNR 1986]

Options:

A) 4

B) 2

C) 3

D) 5

Show Answer

Answer:

Correct Answer: A

Solution:

1.CH3CH2CH2CH2OHButan-1-ol,

2.COOHC,,||,,CH3OH,,CH2CH3

3.CH3CH|,,CH3,CH2OH2 methyl propan-1-ol,

4.CH3C||,,CH3OH,,CH32-Methyl propan-2-ol,



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