Some Basic Principles Of Organic Chemistry Question 250
Question: An organic compound of analysis gave c = 48 g H = 8 g and N = 56 g. Volume of 1.0 g of the compound was found to be 200 ml at NTP. Molecular formula of the compound is
Options:
A) $ C_4H_8N_4 $
B) $ C_2H_4N_2 $
C) $ C_{12}H_{24}N_{12} $
D) $ C_{16}H_{32}N_{16} $
Show Answer
Answer:
Correct Answer: A
Solution:
Element % no.
of moles simple ratio C 48 48/12=4 1 H 8 8/1=8 2 N 56 56/14=4 1 Empirical formula $ =CH_2N $ Empirical formula mass $ =28 $ Now.
200ml of compound $ =1,g $ 22400 ml of compound $ \frac{1}{200}\times 22400=12 $
$ n=\frac{Mol.mass}{Emp,formula,mass}=\frac{112}{28}=4 $ Therefore, molecular formula $ =(CH_2N)_4=C_4H_8N _{4.} $
