Some Basic Principles Of Organic Chemistry Question 161
Question: The number of possible isomers for compound $ C_2H_3Cl_2Br $ is [MP PMT 1999]
Options:
A) 2
B) 3
C) 4
D) 5
Show Answer
Answer:
Correct Answer: B
Solution:
$ C_2H_3Cl_2Br $ Three isomers are possible $ CH_3-C,<-\begin{matrix} Cl \\ Cl \\ Br \\ \end{matrix} $ 1-bromo-1, 1-dichloroethane $ Br-CH_2,-CH<\begin{matrix} Cl \\ {} \\ Br \\ \end{matrix} $ 1-bromo-2, 2-di-chloroethane $ Cl-CH_2,-CH<\begin{matrix} Br \\ {} \\ Cl \\ \end{matrix} $ 1-bromo-1, 2-dichloroethane
