Some Basic Principles Of Organic Chemistry Question 145
Question: How many H-atoms are present in 0.046 g of ethanol [DCE 2003]
Options:
A) $ 6\times 10^{20} $
B) $ 1.2\times 10^{21} $
C) $ 3\times 10^{21} $
D) $ 3.6\times 10^{21} $
Show Answer
Answer:
Correct Answer: D
Solution:
Mol.wt of $ C_2H_5OH $
$ =2\times 12+5+16+1=64 $
$ \because $ $ 48g,C_2H_5OH $ has H atom $ =6\times N_{A} $
$ \therefore $ $ 0.046gC_2H_5OH $ has H atoms $ =\frac{6\times 6.02\times 10^{23}\times 0.046}{46} $
$ =3.6\times 10^{21} $
