Some Basic Principles Of Organic Chemistry Question 140
Question: A gas mixture contains 50% helium and 50% methane by volume. What is the percent by weight of methane in the mixture [Kerala PMT 2004]
Options:
A) 19.97%
B) 20.05%
C) 50%
D) 75%
E) 80.03%
Show Answer
Answer:
Correct Answer: E
Solution:
Solution contain $ He+CH_4 $ Their mol.
wt = $ 4+16=20 $ % wt of $ CH_4 $
$ =\frac{\text{wt of }CH_4}{\text{Total wt}}\times 100 $
$ =\frac{16}{20}\times 100=80.0% $
