SATHEE: Some Basic Principles Of Organic Chemistry Question 139

Some Basic Principles Of Organic Chemistry Question 139

Question: $0.0833, m o l$ of carbohydrate of empirical formula $C H_{2} O$ contain $1 g$ of hydrogen. The molecular formula of the carbohydrate is [DCE 2003; BVP 2004]

Options:

A) $C_{5} H_{10} O_{5}$

B) $C_{3} H_{4} O_{3}$

C) $C_{12} H_{22} O_{11}$

D) $C_{6} H_{12} O_{6}$

Show Answer

Answer:

Correct Answer: D

Solution:

$∵$ 0.0833 mole carbohydrate has hydrogen = $1 g$
$∴$ 1 mole carbohydrate has hydrogen $= \frac{1}{0.0833} = 12 g$ Empirical Formula $(C H_{2} O)$ has hydrogen $= 2 g$ Hence $n = \frac{12}{2} = 6$ Hence molecular formula of carbohydrate $= {(C H_{2} O)}_{6}$

$= C_{6} H_{12} O_{6}$

Some Basic Principles Of Organic Chemistry Question 139

Question: $0.0833, m o l$ of carbohydrate of empirical formula $C H_{2} O$ contain $1 g$ of hydrogen. The molecular formula of the carbohydrate is [DCE 2003; BVP 2004]

Options:

Answer:

Solution:

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Some Basic Principles Of Organic Chemistry Question 139

Question: 0.0833,mol of carbohydrate of empirical formula CH2O contain 1g of hydrogen. The molecular formula of the carbohydrate is [DCE 2003; BVP 2004]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: $0.0833, m o l$ of carbohydrate of empirical formula $C H_{2} O$ contain $1 g$ of hydrogen. The molecular formula of the carbohydrate is [DCE 2003; BVP 2004]