Some Basic Principles Of Organic Chemistry Question 139
Question: $ 0.0833,mol $ of carbohydrate of empirical formula $ CH_2O $ contain $ 1g $ of hydrogen. The molecular formula of the carbohydrate is [DCE 2003; BVP 2004]
Options:
A) $ C_5H_{10}O_5 $
B) $ C_3H_4O_3 $
C) $ C_{12}H_{22}O_{11} $
D) $ C_6H_{12}O_6 $
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Answer:
Correct Answer: D
Solution:
$ \because $ 0.0833 mole carbohydrate has hydrogen = $ 1g $
$ \therefore $ 1 mole carbohydrate has hydrogen $ =\frac{1}{0.0833}=12g $ Empirical Formula $ (CH_2O) $ has hydrogen $ =2g $ Hence $ n=\frac{12}{2}=6 $ Hence molecular formula of carbohydrate $ ={{(CH_2O)}_6} $
$ =C_6H_{12}O_6 $
