Some Basic Principles Of Organic Chemistry Question 108
Question: When 32.25gm ethyl chloride dehydro halogenated, if gives 50%. Alkene, what is the mass of product. (atomic mass of chlorine = 35.5) [Kerala CET 2005]
Options:
A) 14 gm
B) 28 gm
C) 64.5 gm
D) 56 gm
E) 7 gm
Show Answer
Answer:
Correct Answer: E
Solution:
$ C_2H_5Cl $ $ \xrightarrow{-HCl}C_2H_4 $
64.5 28 32.25 28 64.5 gm
$ C_2H_5Cl $ gives 28 gm of $ C_2H_4 $
32.25 gm $ C_2H_5Cl $ gives $ =\frac{28\times 32.25}{64.5} $ = 14 gm of $ C_2H_4 $
Obtained product is 50% so mass of obtained alkene $ =\frac{14}{2}=7,gm $
