Some Basic Principles Of Organic Chemistry Question 104
Question: An organic compound has an empirical formula $ CH_2O $ , its vapour density is 45. The molecular formula of the compounds is [DCE 2004]
Options:
A) $ CH_2O $
B) $ C_2H_5O $
C) $ C_2H_2O $
D) $ C_3H_6O_3 $
Show Answer
Answer:
Correct Answer: D
Solution:
Mol.
wt = 2 $ \times $ Vap.
Density $ =2\times 45=90 $ Empirical formula weight $ =12+2+16=30 $
$ \therefore ,n=\frac{mol\text{.wt}\text{.}}{\text{empirical formula wt}\text{.}} $
$ =\frac{90}{30}=3 $
$ \therefore $ Molecular formula of the compounds $ ={{(CH_2O)}_3} $
$ =C_3H_6O_3 $
