SATHEE: Some Basic Concepts Of Chemistry Question 76

Some Basic Concepts Of Chemistry Question 76

Question: A 25.0 mm $\times$ 40.0 mm piece of gold foil is 0.25 mm thick. The density of gold is $19.32, g / c m^{3}$ . How many gold atoms are in the sheet? (Atomic weight: Au = 197.0)

Options:

A) $7.7 \times 10^{23}$

B) $1.5 \times 10^{23}$

C) $4.3 \times 10^{21}$

D) $1.47 \times 10^{22}$

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Answer:

Correct Answer: D

Solution:

[d] Volume of gold foil $= 25 \times 40 \times 0.25 m m^{3}$ $= 250 \times 10^{- 3} c m^{3}$ Mass of gold foil $= 19.32 \times 250 \times 10^{- 3} g$ $= 4.83 g$ No. of gold atoms $= \frac{4.83}{197} \times N_{A}$ $= 1.47 \times 10^{22}$

Some Basic Concepts Of Chemistry Question 76

Question: A 25.0 mm $\times$ 40.0 mm piece of gold foil is 0.25 mm thick. The density of gold is $19.32, g / c m^{3}$ . How many gold atoms are in the sheet? (Atomic weight: Au = 197.0)

Options:

Answer:

Solution:

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Some Basic Concepts Of Chemistry Question 76

Question: A 25.0 mm × 40.0 mm piece of gold foil is 0.25 mm thick. The density of gold is 19.32,g/cm3 . How many gold atoms are in the sheet? (Atomic weight: Au = 197.0)

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: A 25.0 mm $\times$ 40.0 mm piece of gold foil is 0.25 mm thick. The density of gold is $19.32, g / c m^{3}$ . How many gold atoms are in the sheet? (Atomic weight: Au = 197.0)