Some Basic Concepts Of Chemistry Question 65
Question: How many moles of $ P _4 $ can be produced by reaction of 0.10 moles $ Ca _5{{(PO _4)}_3}F,0.36 $ moles $ SiO _2 $ and 0.90 moles C according to the following reaction?
$ 4Ca _5{{( PO _4 )}_3}F+18SiO _2+30C\xrightarrow{{}} $ $ 3P _4+2CaF _2+18CaSiO _3+30CO $
Options:
A) 0.060
B) 0.030
C) 0.045
D) 0.075
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ 4Ca _5{{( PO _4 )}_3}F+18\underset{0.36}{\overset{L.R.}{\mathop{Si}}},O _2+\underset{0.9}{\mathop{30C}},\xrightarrow{{}}3P _4+2CaF _2 $ $ +18CaSiO _3+30CO $ 18 moles of $ SiO _2 $ gives 3 moles of $ P _4 $ 0.36 moles of $ SiO _2 $ will give $ =\frac{3}{18}\times 0.36=0.06 $ mole
