Some Basic Concepts Of Chemistry Question 296
Question: In the final answer of the expression $ \frac{(29.2-20.2),(1.79\times 10^{5})}{1.37} $ . The number of significant figures is [CBSE PMT 1994]
Options:
A) 1
B) 2
C) 3
D) 4
Show Answer
Answer:
Correct Answer: B
Solution:
$ \frac{(29.2-20.2)\ (1.79\times 10^{5})}{1.37} $ $ =\frac{9.0\times 1.79\times 10^{5}}{1.37} $ Least precise terms i.e., 9.0 has only two significant figures. Hence, final answer will have two significant figures.
