Some Basic Concepts Of Chemistry Question 296

Question: In the final answer of the expression $ \frac{(29.2-20.2),(1.79\times 10^{5})}{1.37} $ . The number of significant figures is [CBSE PMT 1994]

Options:

A) 1

B) 2

C) 3

D) 4

Show Answer

Answer:

Correct Answer: B

Solution:

$ \frac{(29.2-20.2)\ (1.79\times 10^{5})}{1.37} $ $ =\frac{9.0\times 1.79\times 10^{5}}{1.37} $ Least precise terms i.e., 9.0 has only two significant figures. Hence, final answer will have two significant figures.



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