Some Basic Concepts Of Chemistry Question 29

Question: Dissolving 120 g of a compound of mol. wt. 60 in 1000 g of water gave a solution of density 1.12 g/mL. The molarity of the solution is:

Options:

A) $ 1.00 M $

B) $ 2.00M $

C) $ 2.50M $

D) $ 4.00M $

Show Answer

Answer:

Correct Answer: B

Solution:

[b] Given mass of solute (w) = 120 g mass of solvent (w) = 1000 g Mol. mass of solute = 60 g density of solution = 1.12 g/ mL From the given data, Mass of solution $ ~=1000+120=1120g $

$ \because d=\frac{Mol.mass}{V}or,V=\frac{Mol.mass}{d} $ Volume of solution $ ~V=\frac{1120}{1.12}=1000mL $ or = 1 litre Now molarity $ ( M )=\frac{W}{Mol.mass\times V(lit)} $

$ =\frac{120}{60\times 1}=2M $



NCERT Chapter Video Solution

Dual Pane