SATHEE: Some Basic Concepts Of Chemistry Question 276

Some Basic Concepts Of Chemistry Question 276

Question: If $10^{21}$ molecules are removed from 200mg of $C O_{2}$ , then the number of moles of $C O_{2}$ left are [IIT 1983]

Options:

A) $2.85 \times 10^{- 3}$

B) $28.8 \times 10^{- 3}$

C) $0.288 \times 10^{- 3}$

D) $1.68 \times 10^{- 2}$

Show Answer

Answer:

Correct Answer: A

Solution:

200mg of $C O_{2}$ = $200 \times 10^{- 3} = 0.2 g m$

44gm of $C O_{2}$ = $6 \times 10^{23}$ molecules 0.2gm of $C O_{2}$ = $\frac{6 \times 10^{23}}{44} \times 0.2 = 0.0272 \times 10^{23}$

$= 2.72 \times 10^{21}$ molecule Now $10^{21}$ molecule are removed. So remaining molecules $= 2.72 \times 10^{21} - 10^{21}$ $= 10^{21} (2.72 - 1)$ = $1.72 \times 10^{21}$ molecules Now, $6.023 \times 10^{23}$ molecules = 1mole $1.72 \times 10^{21}$ molecules $= \frac{1 \times 1.72 \times 10^{21}}{6.023 \times 10^{23}} = 0.285 \times 10^{- 2}$

$= 2.85 \times 10^{- 3}$ .

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Some Basic Concepts Of Chemistry Question 276

Question: If 1021 molecules are removed from 200mg of CO2 , then the number of moles of CO2 left are [IIT 1983]

Options:

Answer:

Solution:

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Question: If $10^{21}$ molecules are removed from 200mg of $C O_{2}$ , then the number of moles of $C O_{2}$ left are [IIT 1983]