Some Basic Concepts Of Chemistry Question 25
Question: The number of water molecules present in a drop of water (volume 0.0018 mL) density = $ 18m{L^{-1}} $ at room temperature is
Options:
A) $ 1.084\times 10^{18} $
B) $ 6.023\times 10^{19} $
C) $ 4.84\times 10^{17} $
D) $ 6.023\times 10^{23} $
Show Answer
Answer:
Correct Answer: B
Solution:
[b] $ 0.0018mL=0.0018g=0.0001 $ mole of water $ ={10^{-4}},mole $
$ \therefore $ Number of water molecules $ =6.023\times 10^{23}\times {10^{-4}}=6.023\times 10^{19} $
