SATHEE: Some Basic Concepts Of Chemistry Question 25

Some Basic Concepts Of Chemistry Question 25

Question: The number of water molecules present in a drop of water (volume 0.0018 mL) density = $18 m L^{- 1}$ at room temperature is

Options:

A) $1.084 \times 10^{18}$

B) $6.023 \times 10^{19}$

C) $4.84 \times 10^{17}$

D) $6.023 \times 10^{23}$

Show Answer

Answer:

Correct Answer: B

Solution:

[b] $0.0018 m L = 0.0018 g = 0.0001$ mole of water $= 10^{- 4}, m o l e$
$∴$ Number of water molecules $= 6.023 \times 10^{23} \times 10^{- 4} = 6.023 \times 10^{19}$

Some Basic Concepts Of Chemistry Question 25

Question: The number of water molecules present in a drop of water (volume 0.0018 mL) density = $18 m L^{- 1}$ at room temperature is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

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Sample Mock Test

Mentorship

NCERT Exercise Video Solution

Some Basic Concepts Of Chemistry Question 25

Question: The number of water molecules present in a drop of water (volume 0.0018 mL) density = 18mL−1 at room temperature is

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: The number of water molecules present in a drop of water (volume 0.0018 mL) density = $18 m L^{- 1}$ at room temperature is