Some Basic Concepts Of Chemistry Question 237
Question: $ KMnO _4 $ reacts with oxalic acid according to the equation, $ 2MnO_4^{-}+5C _2O_4^{2-}+16{H^{+}}\to 2M{n^{2+}}+10CO _2+8H _2O $ , here 20 ml of 0.1 M $ KMnO _4 $ is equivalent to [CBSE PMT 1996]
Options:
A) 20 ml of 0.5 M $ H _2C _2O _4 $
B) 50 ml of 0.1 M $ H _2C _2O _4 $
C) 50 ml of 0.5 M $ H _2C _2O _4 $
D) 20 ml of 0.1 M $ H _2C _2O _4 $
Show Answer
Answer:
Correct Answer: B
Solution:
$ KMnO _4 $ Oxalic acid $ \frac{M _1V _1}{n _1}= $ $ \frac{M _2V _2}{n _2} $ ; $ \frac{20\times 0.1}{2}=\frac{M _2V _2}{5} $ ; $ M _2V _2=5 $ .
