Some Basic Concepts Of Chemistry Question 212

Question: How much of NaOH is required to neutralise 1500 cm3 of 0.1 N,HCl (Na = 23) [KCET 2001]

Options:

A) 40 g

B) 4 g

C) 6 g

D) 60 g

Show Answer

Answer:

Correct Answer: C

Solution:

N=W(gm)×1000V×Eq.wt.

1500ml of 0.1N HCl = 150ml (N) 1=W(gm)×1000150×40 , W (gm) =150×401000=6gm .



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