Some Basic Concepts Of Chemistry Question 207
Question: The equivalent weight of a metal is 9 and vapour density of its chloride is 59.25. The atomic weight of metal is [Pb. CET 2002]
Options:
A) 23.9
B) 27.3
C) 36.3
D) 48.3
Show Answer
Answer:
Correct Answer: A
Solution:
Given equivalent weight of metal = 9 Vapour density of metal chloride = 59.25
$ \therefore $ molecular weight of metal chloride $ =2\times V.D=2\times 59.25=118.5 $
$ \therefore $ valency of metal $ =\frac{\text{molecular weight of metal chloride}}{\text{equivalnet weight of metal }+35\text{.5}} $
Valency of metal $ =\frac{118.5}{9+35.5}=\frac{118.5}{44.5}=2.66 $
Therefore atomic weight of the metal =equivalent weight $ \times $ valency $ =9\times 2.66=23.9 $
