SATHEE: Some Basic Concepts Of Chemistry Question 183

Some Basic Concepts Of Chemistry Question 183

Question: Ratio of $C_{p}$ and $C_{v}$ of a gas X is 1.4, the number of atom of the gas ?X? present in 11.2 litres of it at NTP will be [CBSE 1999]

Options:

A) $6.02 \times 10^{23}$

B) $1.2 \times 10^{23}$

C) $3.01 \times 10^{23}$

D) $2.01 \times 10^{23}$

Show Answer

Answer:

Correct Answer: A

Solution:

$\frac{C_{P}}{C_{V}} = 1.4$ so, given gas is diatomic 11.2L $= 3.01 \times 10^{23}$ molecules
$∴$ No. of atoms $= 3.01 \times 10^{23} \times 2$ $= 6.023 \times 10^{23}$ atoms

Some Basic Concepts Of Chemistry Question 183

Question: Ratio of $C_{p}$ and $C_{v}$ of a gas X is 1.4, the number of atom of the gas ?X? present in 11.2 litres of it at NTP will be [CBSE 1999]

Options:

Answer:

Solution:

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Some Basic Concepts Of Chemistry Question 183

Question: Ratio of Cp and Cv of a gas X is 1.4, the number of atom of the gas ?X? present in 11.2 litres of it at NTP will be [CBSE 1999]

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: Ratio of $C_{p}$ and $C_{v}$ of a gas X is 1.4, the number of atom of the gas ?X? present in 11.2 litres of it at NTP will be [CBSE 1999]