Some Basic Concepts Of Chemistry Question 167

Question: The number of atoms in 4.25 g of $ NH _3 $ is approximately [CBSE PMT 1999; MH CET 2003]

Options:

A) $ 1\times 10^{23} $

B) $ 2\times 10^{23} $

C) $ 4\times 10^{23} $

D) $ 6\times 10^{23} $

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Answer:

Correct Answer: D

Solution:

$ \because $ 17gm $ NH _3 $ contains $ 6\times 10^{23} $ molecules of $ NH _3 $

$ \therefore $ 4.25gm $ NH _3 $ contains = $ \frac{6\times 10^{23}}{17}\times 4.25 $

$ \therefore $ No. of atoms $ =\frac{6\times 10^{23}\times 4.25}{17}\times 4 $ $ =6\times 10^{23} $ .



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