Some Basic Concepts Of Chemistry Question 167

Question: The number of atoms in 4.25 g of NH3 is approximately [CBSE PMT 1999; MH CET 2003]

Options:

A) 1×1023

B) 2×1023

C) 4×1023

D) 6×1023

Show Answer

Answer:

Correct Answer: D

Solution:

17gm NH3 contains 6×1023 molecules of NH3

4.25gm NH3 contains = 6×102317×4.25

No. of atoms =6×1023×4.2517×4 =6×1023 .



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