Some Basic Concepts Of Chemistry Question 167
Question: The number of atoms in 4.25 g of $ NH _3 $ is approximately [CBSE PMT 1999; MH CET 2003]
Options:
A) $ 1\times 10^{23} $
B) $ 2\times 10^{23} $
C) $ 4\times 10^{23} $
D) $ 6\times 10^{23} $
Show Answer
Answer:
Correct Answer: D
Solution:
$ \because $ 17gm $ NH _3 $ contains $ 6\times 10^{23} $ molecules of $ NH _3 $
$ \therefore $ 4.25gm $ NH _3 $ contains = $ \frac{6\times 10^{23}}{17}\times 4.25 $
$ \therefore $ No. of atoms $ =\frac{6\times 10^{23}\times 4.25}{17}\times 4 $ $ =6\times 10^{23} $ .
