SATHEE: Some Basic Concepts Of Chemistry Question 155

Some Basic Concepts Of Chemistry Question 155

Question: About $6 \times 10^{- 3}$ mol $K_{2} C r_{2} O_{7}$ reacts completely with $9 \times 10^{- 3}$ mol $X^{n +}$ to give $X {O^{-}}_{3}$ and $C r^{3 +}$ . The value of $n$ is:

Options:

A) 1

B) 2

C) 3

D) none of these

Show Answer

Answer:

Correct Answer: A

Solution:

[a] $K_{2} C r_{2} O_{7} + X^{n +} \to X^{5 +} O_{3}^{-} + C r^{3 +}$ $6 \times 10^{- 3} \times 6 = (5 - n) \times 9 \times 10^{- 3} \Rightarrow, n = 1$

Some Basic Concepts Of Chemistry Question 155

Question: About $6 \times 10^{- 3}$ mol $K_{2} C r_{2} O_{7}$ reacts completely with $9 \times 10^{- 3}$ mol $X^{n +}$ to give $X {O^{-}}_{3}$ and $C r^{3 +}$ . The value of $n$ is:

Options:

Answer:

Solution:

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Some Basic Concepts Of Chemistry Question 155

Question: About 6×10−3 mol K2Cr2O7 reacts completely with 9×10−3 mol Xn+ to give XO−3 and Cr3+ . The value of n is:

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: About $6 \times 10^{- 3}$ mol $K_{2} C r_{2} O_{7}$ reacts completely with $9 \times 10^{- 3}$ mol $X^{n +}$ to give $X {O^{-}}_{3}$ and $C r^{3 +}$ . The value of $n$ is: