Some Basic Concepts Of Chemistry Question 151

Question: How many H-atoms are present in 0.046 got ethanol?

Options:

A) $ 6\times 10^{20} $

B) $ 1.2\times 10^{21} $

C) $ 3\times 10^{21} $

D) $ 3.6\times 10^{21} $

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Answer:

Correct Answer: D

Solution:

[d] Molecular weight of $ C _2H _5OH=2\times 12+5+16+1=64 $

$ \because $ 48 g $ C _2H _5OH $ has H atom $ =6\times N _{A} $

$ \therefore $ 0.046 g $ C _2H _5OH $ has H atoms $ =\frac{6\times 6.02\times 10^{23}\times 0.046}{46}=3.6\times 10^{21} $



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