Some Basic Concepts Of Chemistry Question 151
Question: How many H-atoms are present in 0.046 got ethanol?
Options:
A) $ 6\times 10^{20} $
B) $ 1.2\times 10^{21} $
C) $ 3\times 10^{21} $
D) $ 3.6\times 10^{21} $
Show Answer
Answer:
Correct Answer: D
Solution:
[d] Molecular weight of $ C _2H _5OH=2\times 12+5+16+1=64 $
$ \because $ 48 g $ C _2H _5OH $ has H atom $ =6\times N _{A} $
$ \therefore $ 0.046 g $ C _2H _5OH $ has H atoms $ =\frac{6\times 6.02\times 10^{23}\times 0.046}{46}=3.6\times 10^{21} $
