SATHEE: Some Basic Concepts Of Chemistry Question 149

Some Basic Concepts Of Chemistry Question 149

Question: 1 mol of a gaseous aliphahatic compound $C_{n} H_{3 n} O_{m}$ is completely burnt in an excess of oxygen. The contraction in volume is (assume water get condensed out)

Options:

A) $(1 + \frac{1}{2} n - \frac{3}{4} m)$

B) $(1 + \frac{3}{4} n - \frac{1}{4} m)$

C) $(1 - \frac{1}{2} n - \frac{3}{4} m)$

D) $(1 + \frac{3}{4} n - \frac{1}{2} m)$

Show Answer

Answer:

Correct Answer: D

Solution:

[d] $C_{n} H_{3 n} O_{m} + y O_{2} \to_{}^{} n C o_{2} (g) + \frac{3 n}{2} H_{2} O (l)$ Contraction in volume= Contraction in moles of gas $= 1 \frac{3 n}{4} - \frac{m}{2}$

$= 1 + \frac{3 n}{4} - \frac{m}{2}$

$\Rightarrow$ $(2 n + \frac{3 n}{2} - m) \times \frac{1}{2} = y$

$\Rightarrow$ $n + \frac{3 n}{4} - \frac{m}{2} = y$

Some Basic Concepts Of Chemistry Question 149

Question: 1 mol of a gaseous aliphahatic compound $C_{n} H_{3 n} O_{m}$ is completely burnt in an excess of oxygen. The contraction in volume is (assume water get condensed out)

Options:

Answer:

Solution:

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Some Basic Concepts Of Chemistry Question 149

Question: 1 mol of a gaseous aliphahatic compound CnH3nOm is completely burnt in an excess of oxygen. The contraction in volume is (assume water get condensed out)

Options:

Answer:

Solution:

Engineering Preparation

Medical Preparation

NCERT Books & Solutions

Important Resources

Other Resources

Syllabus

Test Platform

Sample Mock Test

Mentorship

NCERT Exercise Video Solution

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Question: 1 mol of a gaseous aliphahatic compound $C_{n} H_{3 n} O_{m}$ is completely burnt in an excess of oxygen. The contraction in volume is (assume water get condensed out)