Some Basic Concepts Of Chemistry Question 149

Question: 1 mol of a gaseous aliphahatic compound $ C _{n}H _{3n}O _{m} $ is completely burnt in an excess of oxygen. The contraction in volume is (assume water get condensed out)

Options:

A) $ ( 1+\frac{1}{2}n-\frac{3}{4}m ) $

B) $ ( 1+\frac{3}{4}n-\frac{1}{4}m ) $

C) $ ( 1-\frac{1}{2}n-\frac{3}{4}m ) $

D) $ ( 1+\frac{3}{4}n-\frac{1}{2}m ) $

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Answer:

Correct Answer: D

Solution:

[d] $ C _{n}H _{3n}O _{m}+yO _2\xrightarrow[{}]{{}}nCo _2(g)+\frac{3n}{2}H _2O(l) $ Contraction in volume= Contraction in moles of gas $ =1\frac{3n}{4}-\frac{m}{2} $

$ =1+\frac{3n}{4}-\frac{m}{2} $

$ \Rightarrow $ $ ( 2n+\frac{3n}{2}-m )\times \frac{1}{2}=y $

$ \Rightarrow $ $ n+\frac{3n}{4}-\frac{m}{2}=y $



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