Some Basic Concepts Of Chemistry Question 13

Question: If 0.5 mole of $ BaCl _2 $ is mixed with 0,20 mole of $ Na _3PO _4 $ , the maximum number of moles of $ Ba _3(PO _4) $ that can be formed is

Options:

A) 0.1

B) 0.2

C) 0.5

D) 0.7

Show Answer

Answer:

Correct Answer: A

Solution:

$ \underset{[3,mol}{\mathop{3BaCl _2}},+\underset{2,mol}{\mathop{2Na _3PO _4}},\to \underset{6,mol}{\mathop{6NaCl}},+\underset{1,mol]}{\mathop{Ba _3{{(PO _4)}_2}}}, $ Given
$ \Rightarrow $ 0.5 mol of $ BaCl _2 $ and 0.2 mol of $ Na _3PO _4 $ To find the limiting reagent: 2 mol of $ Na _3PO _4 $
$ \Rightarrow $ 3 mol of $ BaCl _2 $ 0.2 mol of $ Na _3PO _4 $
$ \Rightarrow $ 0.3 mol of $ BaCl _2 $
$ \therefore $ $ Na _3PO _4 $ is the limiting reagent
$ \therefore $ 2 mol of $ Na _3PO _4 $
$ \Rightarrow $ 1 mol of $ Ba _3{{(PO _4)}_2} $ 0.2 mol of $ Na _3PO _4 $
$ \Rightarrow $ 0.1 mol of $ Ba _3{{(PO _4)}_2} $



NCERT Chapter Video Solution

Dual Pane