Some Basic Concepts Of Chemistry Question 126

Question: Calcium carbonate reacts with aqueous HCl to give CaCl2 and CO2 according to the reaction,

CaCO3(s)+2HCl(aq) CaCl2(aq)+CO2(g)+H2O(l) In this reaction, 250 mL of 0.76 M HCI reacts with 1000 g of CaCO3. Calculate the mass of CaCl2 formed in the reaction.

Options:

A) 11.1 g

B) 10.54 g

C) 5.25 g

D) 2.45 L

Show Answer

Answer:

Correct Answer: B

Solution:

[b] Molar mass of CaCO3=40+12+3×16=100gmol1 Moles of CaCO3 in 1000 g. nCaCO3=Mass(g)Molar,mass

nCaCO3=1000100g,mol1=10,mol

molarity=Moles,of,solute(HCl) × 100Volume,of,solution

0.76=nHCl×1000250

nHCl=0.76×25010000.19,mol

CaCO3(s)1mol+2HCl(aq)2,mol,CaCl2(aq)+ CO2(g)+H2O(l) According to the equation, 1 mole of CaCO3 reacts with 2 moles of HCl

10 moles of CaCO3 will react with 10×21=20 moles of HCI. But we have only 0.19 moles HCl, so HCl is the limiting reagent and it limits the yield of CaCl2 . 0.19 moles of HCl will produce 1×0.192=0.095,mol,CaCl2. Molar mass of CaCl2=40+(2×,35.5)=111,g,mol

0.095 mole of
CaCl2=0.095×111=10.54,g



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