Some Basic Concepts Of Chemistry Question 122

Question: What is the atomic weight of an element X for which a sample containing $ 1.58\times 10^{22} $ atoms weigh 1.05 g?

Options:

A) 28 g

B) 20 g

C) 40 g

D) 23 g

Show Answer

Answer:

Correct Answer: C

Solution:

[c] We know that, one mole of an element $ =6.02\times 10^{23} $ atoms = Atomic weight of the element Now, $ 1.58\times 10^{22} $ atoms weigh 1.05 g

$ \therefore $ $ 6.02\times 10^{23} $ atoms weigh
$ =\frac{(1.05\times 6.02\times 10^{23})}{1.58\times 10^{22}} $
= 40 g Atomic weight of $ X=40g $



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