Some Basic Concepts Of Chemistry Question 117
Question: How many grams of caustic potash required to completely neutralise 12.6 gm $ HNO _3 $
Options:
A) 22.4 KOH
B) 1.01 KOH
C) 6.02 KOH
D) 11.2 KOH
Show Answer
Answer:
Correct Answer: D
Solution:
$ HNO _3+KOH\to KNO _3+H _2O $
$ \frac{12.6}{63}= $ 0.2 mole; $ HNO _3\equiv KOH $ 0.2 mole $ \equiv $ 0.2 mole $ 0.2\times 56=11.2gm $ .
