Some Basic Concepts Of Chemistry Question 114
Question: What should be the weight and moles of $ AgCl $ precipitate obtained on adding 500ml of 0.20 M $ HCl $ in 30 g of $ AgNO _3 $ solution? ( $ AgNO _3 $ = 170)
Options:
A) 14.35 g
B) 15 g
C) 18 g
D) 19 g
Show Answer
Answer:
Correct Answer: A
Solution:
[a] $ AgNO _3+HCl\to AgCl+HNO _3 $
$ \frac{30}{170} $ $ \frac{500\times 0.2}{1000} $ t =0 0.176 mole 0.1 mole limiting =14.345gm
