Some Basic Concepts Of Chemistry Question 113

Question: The ratio of amounts of $ H _2S $ needed to precipitate all the metal ions from 100 ml of 1 M $ AgNO _3 $ and 100 ml of 1 M $ CuSO _4 $ will be

Options:

A) 1:1

B) 1:2

C) 2:1

D) None of these

Show Answer

Answer:

Correct Answer: B

Solution:

[b] $ AgNO _3\equiv 2A{g^{+}}+\underset{(H _2S)}{\mathop{{S^{2-}}}},\to Ag _2S $

$ \because $ 2 mole $ \to $ 1 mole [100×1 =100 millimole]

$ \therefore $ 100 miliimole $ \to $ 50 millimole $ H _2S $ required $ CuSO _4\equiv C{u^{+2}}+\underset{(H _2S)}{\mathop{{S^{2-}}}},\to CuS $

$ \because $ 1 mole $ \to $ 1 mole [100×1=100 millimole]

$ \therefore $ 100 millimole $ \to $ 100 millimole $ H _2S $ required Ratio $ \frac{50}{100}=\frac{1}{2} $ .



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